Re: 8088 and 610 saga continues...

From: Michał Pleban <>
Date: Wed, 26 Jan 2011 13:32:47 +0100
Message-ID: <>

W dniu 2011-01-26 11:40, Hársfalvi Levente pisze:

> Small correction... 64kbits chips, although the multiplexed address
> input is 8 bits wide, still need 7-bit refresh counters (128 refresh
> cycles). 8 bit refresh counters and above are needed from 41464 and
> 41256 (64kx4, 256kx1 = 256kbit) and on.

That could be a good explanation then. So it looks like the $21 value is
presented on the address bus, then something goes wrong with DRAM
control lines and this value is used bogus "refresh" operation which
does not refresh, but instead destroys data in given row. Does it make
any sense?


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Received on 2011-01-26 13:00:09

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