Hallo Martijn, > A-symmetrical stream #3: (101000): > > This one is totaly devastated. It hardly represents the signal it's supposed > to be; there are -0v crossings where there shouldn't have been; the peak At this moment I have so many questions that the mailserver certainly will bumo this email. The problem isthat I have some knowledge of the hardware of a CD-player and in this case it does not help. For one thing, there are DAC's inside a CD-player and they need bits to make a sample. And this information does not match with yours saying you put some bit patterns on a CD and they don't come out exactly as expected. My first gues would be they would not come out at all as expected. But they partly do so: confusion :( If I got you right, in case of the 101000 bitstream you wanted to end up with a wave-pattern which should look as similar as the bitpattern itself. But it doesn't. My idea: what about recording some known "music"-bitpatterns and then to look on the CD hoe the real bit pattern looks like? Another idea: whabout only using the 22 and 11 KHz-signal? 22 KHz = 0 and 11 KHZ = 1. so 1010 1100 1010 1100 1100 1100 1010 1010 means: 0 1 0 1 1 1 0 0 This still means 11 Kbit/sec or 1 KByte (including sart and two stopbits). Groetjes, Ruud - This message was sent through the cbm-hackers mailing list. To unsubscribe: echo unsubscribe | mail firstname.lastname@example.org.
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