Re: Data storage on CD-Audio -- bad news.
Date: 1999-10-23 22:37:17

Hallo Martijn,

> A-symmetrical stream #3: (101000):
> This one is totaly devastated. It hardly represents the signal it's supposed
> to be; there are -0v crossings where there shouldn't have been; the peak

At this moment I have so many questions that the mailserver certainly will bumo 
this email. The problem isthat I have some knowledge of the hardware of a 
CD-player and in this case it does not help. For one thing, there are DAC's 
inside a CD-player and they need bits to make a sample. And this information 
does not match with yours saying you put some bit patterns on a CD and they 
don't come out exactly as expected. My first gues would be they would not come 
out at all as expected. But they partly do so: confusion :(

If I got you right, in case of the 101000 bitstream you wanted to end up with a 
wave-pattern which should look as similar as the bitpattern itself. But it 
doesn't. My idea: what about recording some known "music"-bitpatterns and then 
to look on the CD hoe the real bit pattern looks like?

Another idea: whabout only using the 22 and 11 KHz-signal? 22 KHz = 0 and 11 
KHZ = 1.
so 1010 1100 1010 1100 1100 1100 1010 1010 means:
     0    1    0    1    1    1    0    0
This still means 11 Kbit/sec or 1 KByte (including sart and two stopbits). 

Groetjes, Ruud

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