On 09/22/2012 05:55 PM, firstname.lastname@example.org wrote: > > On 2012-09-22, at 17:29, Gerrit Heitsch wrote: > >>>>> BTW, Gerrit - what do you think was the point in providing two +5Vs in the 64? One called +5 and the other CAN+5? Looking at 252312-right, they dropped this idea on the narrow boards. But I am wondering why they introduced it in the first place. >>>> >>>> There are 3 reasons I can imagine: >>>> >>>> 1) Power, 5V, 2A might have needed a different plug >>> >>> I think this DIN should handle 2A w/o problems but In fact I am not sure about the actual specs. >> >> Hm... It would be borderline... If the contacts are just a bit worn, you start having a measurable voltage drop on the connection. > > But there are two pins allocated for +5. Just by adding second pin to the plug they could have doubled the current there. You also need 2 pins for GND to make that work properly. Otherwise you still have a bottleneck. > First I simply bent out pin 40 out of the socket and supplied it with +5 from the PWR switch. I noticed (really barely) a degradation to the picture quality but when supplying the same pin with CAN+5, there was virtually no difference. Meaning also a slight (if at all) degradation of the quality. So I decided to do better test and keep the two decoupling capacitors in the loop. So I cut the trace and installed a pinhead like here: > > https://dl.dropbox.com/u/58002657/vic_pwr_supply.jpg > > and after switching back and forth the supply between +5 and CAN+5 I don't see any difference. > > So as the last iteration I removed pin 2 of 7805 and supplied the pad with +5. > > https://dl.dropbox.com/u/58002657/whole_can%2B5_replaced.jpg > > Again - no noticeable difference at least on the screen. Maybe on a scope someone could notice something but on the screen I see no noticeable difference. > > After doing this I tend to believe that it must have been something around 2) or something about utilising the PSU's current capacity better. Possibly... Maybe they wanted to equalize the load on the 2 outputs of the transformer. On the other hand, the 250469-boards put almost all of the load on the +5V (about 1.1A) and almost nothing on 9V AC. But while you're at it... if you feel like it, you could find out what's the minimal Vdd (usually +12V, pin 13) for VIC to give you a picture with colors. My last attempt was 3 diodes (1N4001) in series, lowering the voltage on pin 13 from 12V to about 10V and still everything worked. From my experience with a dead C90, I know that there is a voltage where everything still works but the picture loses color. For the 6569R3 involved that was about 8V. Gerrit Message was sent through the cbm-hackers mailing listReceived on 2012-09-22 17:00:14
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