Re: 'Divide by A' procedure in 90x0 ROM

From: Rhialto <>
Date: Sat, 19 Feb 2011 01:35:29 +0100
Message-ID: <>
On Sat 19 Feb 2011 at 01:31:33 +0100, Rhialto wrote:
> Also, with the 18 x going through the loop instead of 16 x, it looks
> like it does it too often, which results in the wrong answer by a factor
> of 4...

Ah, no, I misread that. Since we're working on 3-byte values here, the
loop needs to be done 24 x and it was $18 in that source.

___ Olaf 'Rhialto' Seibert  -- There's no point being grown-up if you 
\X/ rhialto/at/    -- can't be childish sometimes. -The 4th Doctor

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Received on 2011-02-19 01:00:22

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