RE: Order of sectors on a track

RE: Order of sectors on a track

Date: Mon, 25 May 2009 13:14:05 +0200
Message-ID: <>
Hallo Ingo,

> You seem to use very slow code for that

I use the code found at $F3B1. 

>	cpy #$04

$F3B1 decodes the whole header. And it looks as if EXOS only decodes the
first three bytes. Which means there is quite some time left to do this.
Thanks for the info!

>	jsr $f82b               ; convert $0302-? to binary

I assume that this is the same routine as found in the original 1541
DOS? The first four instruction found at this address cannot be found in
the JD sources so I assume that JD uses a different routine.

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Received on 2009-05-25 14:23:32

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