From: Scott McDonnell (netsamurai_at_comcast.net)
Date: 2007-04-07 07:16:16
Daniel, Wow, that is an old post. Looking back at it, I am not 100% sure of the reason I suggested the transistor instead of just inserting the 0-5V source, since the potentiometer is just being used as a voltage divider. The only purpose that seems obvious to me right now was that I was probably aiming at protecting the control port by isolating the control circuit from the commodore. If the grounds between the two devices where to get disconnected, the voltage could become unpredictable and possibly create a damaging voltage situation. Ground is not 0V, but is a reference, +5V just means 5V above ground in the circuit. Using the transistor would allow you to use the 5V and ground from the control port, in effect (at least partially) isolating the two circuits. I see talk about "current source" there, which implies to me that I was trying to explain the way the SID ADC works. Hmm...at the time of writing that, I seem to recall that I was studying the internal circuitry of the SID. I will have to look into this again and get back to you, it has been a while. The question is, was I just using a sledgehammer to pound in a nail? Scott McDonnell -----Original Message----- From: email@example.com [mailto:firstname.lastname@example.org] On Behalf Of Daniel O'Shea Sent: Friday, April 06, 2007 10:26 PM To: email@example.com Subject: Re: Commodore joystick ports ...replying to quite an old message here, but it has given me an answer I've been looking for and I'm hoping that someone will be able to elaborate a little! I have a variable voltage of 0 to 5V, and I want to translate this in to a current to simulate the variable resistance of a potentiometer connected to the SID's ADC - Scott suggests using a transistor, but I want to know what kind of transistor and what value would work best to provide a variable current which duplicates the potentiometer's variable current? and do I need any extra components besides just a transistor? thanks! > ----- Original Message ----- > Re: Commodore joystick ports > From: Scott McDonnell (NetSamurai_at_comcast.net) > Date: 2004-10-22 20:44:06 > > Jim, > > As Hársfalvi mentioned, it is current that needs to be generated, not > voltage. A resistor creates a voltage drop across it, which is a > function of current. (Resistance=Current/Voltage) The voltage is 5V, > the resitance is a range that you know from the potentiometer values, > you simply need to create the corresponding current to emulate the > resistance you need. > > A transistor in this mode (current source) should be thought of as a > valve. The valve is completely shut off when no voltage is applied to > the base. This allows the SID to discharge the capacitor (when it is > shorting for 256 > cycles) without drawing in the 5V. By varying the voltage to the base, you > are opening the valve by a varying degree, varying the amount of current > which is allowed to flow. > > You are correct in assuming that you will need an analog voltage at > the base (but not to bias it, that is for amplication - to carry an AC > signal through the transistor - you are simply using it like a valve.) > If your micro does not have a DAC built in, you can build an R-2R > ladder DAC, like the one showing here: > http://www.hut.fi/Misc/Electronics/circuits/r2r.html or a Summing DAC > like here: > http://www.phys.ualberta.ca/~gingrich/phys395/notes/node162.html > (without the op-amp). Obviously, the values of the resistors in the > circuit may need to be altered a bit to get the range of voltages you > desire. This will be based on some calculations, which are not > extremely difficult. Here's a page you can use for reference: > http://www.williamson-labs.com/480_xtor.htm#voltage-current it > describes and explains how a transistor is used to convert voltage to > current. If you need some more help, drop me a line. I would be > willing to design the circuit for you when I have a spare moment, but > the true satisfaction comes from figuring it out yourself, so I won't > deprive you of that! > > A FET might actually do a better job, but the calculations get a bit > more complex, the cost increases, and is probably not necessary for > the type of resolution you will need. An 8-bit R-2R ladder DAC would > give you 256 voltage values to feed into the base of your transistor, > which would result in 256 different currents at each axis input. > Probably way more resolution than a commodore mouse provides. > > Scott McDonnell Message was sent through the cbm-hackers mailing list Message was sent through the cbm-hackers mailing list
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